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1/5z+4/52=-5
We move all terms to the left:
1/5z+4/52-(-5)=0
Domain of the equation: 5z!=0We add all the numbers together, and all the variables
z!=0/5
z!=0
z∈R
1/5z+5+4/52=0
We calculate fractions
There is no solution for this equation
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