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1/6(0.3x-12)+0.05x=1/4(7-0.4x)
We move all terms to the left:
1/6(0.3x-12)+0.05x-(1/4(7-0.4x))=0
Domain of the equation: 6(0.3x-12)!=0
x∈R
Domain of the equation: 4(7-0.4x))!=0We add all the numbers together, and all the variables
x∈R
1/6(0.3x-12)+0.05x-(1/4(-0.4x+7))=0
We add all the numbers together, and all the variables
0.05x+1/6(0.3x-12)-(1/4(-0.4x+7))=0
We calculate fractions
0.05x+(4x(-)/(6(0.3x-12)*4(-0.4x+7)))+(-6x)/(6(0.3x-12)*4(-0.4x+7)))=0
We calculate terms in parentheses: +(4x(-)/(6(0.3x-12)*4(-0.4x+7))), so:
4x(-)/(6(0.3x-12)*4(-0.4x+7))
We add all the numbers together, and all the variables
4x0/(6(0.3x-12)*4(-0.4x+7))
We multiply all the terms by the denominator
4x0
We add all the numbers together, and all the variables
4x
Back to the equation:
+(4x)
We calculate terms in parentheses: +(-6x)/(6(0.3x-12)*4(-0.4x+7))), so:We add all the numbers together, and all the variables
-6x)/(6(0.3x-12)*4(-0.4x+7))
We multiply all the terms by the denominator
-6x)
Back to the equation:
+(-6x))
4.05x+(-6x))=0
We get rid of parentheses
4.05x-6x)=0
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