1/6(12-18x)+6=3

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Solution for 1/6(12-18x)+6=3 equation: 



1/6(12-18x)+6=3

We move all terms to the left:

1/6(12-18x)+6-(3)=0



Domain of the equation: 6(12-18x)!=0

x∈R



We add all the numbers together, and all the variables

1/6(-18x+12)+6-3=0

We add all the numbers together, and all the variables

1/6(-18x+12)+3=0

We multiply all the terms by the denominator


3*6(-18x+12)+1=0

Wy multiply elements

18x(-+1=0

We use the square of the difference formula

18x(-1=0

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