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x in (-oo:+oo)
(1/6)*(12*x-18) = 2*(x-((1/4)*y)) // - 2*(x-((1/4)*y))
(1/6)*(12*x-18)-(2*(x-((1/4)*y))) = 0
(1/6)*(12*x-18)-2*(x+(-1/4)*y) = 0
1/6*(12*x-18)-2*(x-1/4*y) = 0
1/6*(12*x-18)-2*(x-1/4*y) = 0
1/2*y-3 = 0
1/2*y-3 = 0
x belongs to the empty set
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