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1/6(12x-18)=2x+3
We move all terms to the left:
1/6(12x-18)-(2x+3)=0
Domain of the equation: 6(12x-18)!=0We get rid of parentheses
x∈R
1/6(12x-18)-2x-3=0
We multiply all the terms by the denominator
-2x*6(12x-18)-3*6(12x-18)+1=0
Wy multiply elements
-12x^2(1-18x(1+1=0
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