1/6(12x-72)=1/2(4x-26)

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Solution for 1/6(12x-72)=1/2(4x-26) equation:



1/6(12x-72)=1/2(4x-26)
We move all terms to the left:
1/6(12x-72)-(1/2(4x-26))=0
Domain of the equation: 6(12x-72)!=0
x∈R
Domain of the equation: 2(4x-26))!=0
x∈R
We calculate fractions
(2x4/(6(12x-72)*2(4x-26)))+(-6x1/(6(12x-72)*2(4x-26)))=0
We calculate terms in parentheses: +(2x4/(6(12x-72)*2(4x-26))), so:
2x4/(6(12x-72)*2(4x-26))
We multiply all the terms by the denominator
2x4
We add all the numbers together, and all the variables
2x^4
We do not support expression: x^4

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