1/6(12x-72)=1/2(4x-26)

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Solution for 1/6(12x-72)=1/2(4x-26) equation: 



1/6(12x-72)=1/2(4x-26)

We move all terms to the left:

1/6(12x-72)-(1/2(4x-26))=0



Domain of the equation: 6(12x-72)!=0

x∈R





Domain of the equation: 2(4x-26))!=0

x∈R



We calculate fractions


(2x4/(6(12x-72)*2(4x-26)))+(-6x1/(6(12x-72)*2(4x-26)))=0



We calculate terms in parentheses: +(2x4/(6(12x-72)*2(4x-26))), so:

2x4/(6(12x-72)*2(4x-26))

We multiply all the terms by the denominator


2x4

We add all the numbers together, and all the variables

2x^4

We do not support expression: x^4

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