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1/6(12z+18)=2z+-3
We move all terms to the left:
1/6(12z+18)-(2z+-3)=0
Domain of the equation: 6(12z+18)!=0We add all the numbers together, and all the variables
z∈R
1/6(12z+18)-(2z-3)=0
We get rid of parentheses
1/6(12z+18)-2z+3=0
We multiply all the terms by the denominator
-2z*6(12z+18)+3*6(12z+18)+1=0
Wy multiply elements
-12z^2(1+18z(1+1=0
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