1/6(12z+18)=2z-3

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Solution for 1/6(12z+18)=2z-3 equation: 



1/6(12z+18)=2z-3

We move all terms to the left:

1/6(12z+18)-(2z-3)=0



Domain of the equation: 6(12z+18)!=0

z∈R



We get rid of parentheses

1/6(12z+18)-2z+3=0

We multiply all the terms by the denominator


-2z*6(12z+18)+3*6(12z+18)+1=0

Wy multiply elements

-12z^2(1+18z(1+1=0

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