1/6(12z-18)=2z+3

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Solution for 1/6(12z-18)=2z+3 equation: 



1/6(12z-18)=2z+3

We move all terms to the left:

1/6(12z-18)-(2z+3)=0



Domain of the equation: 6(12z-18)!=0

z∈R



We get rid of parentheses

1/6(12z-18)-2z-3=0

We multiply all the terms by the denominator


-2z*6(12z-18)-3*6(12z-18)+1=0

Wy multiply elements

-12z^2(1-18z(1+1=0

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