1/6(12z-18)=2z-3

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Solution for 1/6(12z-18)=2z-3 equation: 


z in (-oo:+oo)

(1/6)*(12*z-18) = 2*z-3 // - 2*z-3

(1/6)*(12*z-18)-(2*z)+3 = 0

(1/6)*(12*z-18)-2*z+3 = 0

1/6*(12*z-18)-2*z+3 = 0

1/6*(12*z-18)-2*z+3 = 0

3-3 = 0

0 = 0

0 = 0

z belongs to the empty set

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