1/6(12z-18z)=2z-3

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Solution for 1/6(12z-18z)=2z-3 equation: 



1/6(12z-18z)=2z-3

We move all terms to the left:

1/6(12z-18z)-(2z-3)=0



Domain of the equation: 6(12z-18z)!=0

z∈R



We add all the numbers together, and all the variables

1/6(-6z)-(2z-3)=0

We get rid of parentheses

1/6(-6z)-2z+3=0

We multiply all the terms by the denominator


-2z*6(-6z)+3*6(-6z)+1=0

Wy multiply elements

-12z^2(-+18z(-+1=0

We use the square of the difference formula

-12z^2(-18z(-1=0

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