1/6(13+3x)=4/5x

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Solution for 1/6(13+3x)=4/5x equation: 



1/6(13+3x)=4/5x

We move all terms to the left:

1/6(13+3x)-(4/5x)=0



Domain of the equation: 6(13+3x)!=0

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/6(3x+13)-(+4/5x)=0

We get rid of parentheses

1/6(3x+13)-4/5x=0

We calculate fractions


5x/(90x^2+390x)+(-24x3/(90x^2+390x)=0



We calculate terms in parentheses: +(-24x3/(90x^2+390x), so:

-24x3/(90x^2+390x

We multiply all the terms by the denominator


-24x3

We add all the numbers together, and all the variables

-24x^3

We do not support expression: x^3

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