1/6(18a-24b)-1/7(7a-28b-3)-1/5

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Solution for 1/6(18a-24b)-1/7(7a-28b-3)-1/5 equation: 


x in (-oo:+oo)

(1/6)*(18*a-(24*b))-((1/7)*(7*a-(28*b)-3))-(1/5) = 0

(1/6)*(18*a-24*b)+(-1/7)*(7*a-28*b-3)-1/5 = 0

1/6*(18*a-24*b)-1/7*(7*a-28*b-3)-1/5 = 0

(1/6*5*(18*a-24*b))/5+(-1/7*5*(7*a-28*b-3))/5-1/5 = 0

1/6*5*(18*a-24*b)-1/7*5*(7*a-28*b-3)-1 = 0

10*a-1+15/7 = 0

10*a+8/7 = 0

(10*a+8/7)/5 = 0

(10*a+8/7)/5 = 0 // * 5

10*a+8/7 = 0

x belongs to the empty set

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