1/6(2c-1)=1/3c-1/6

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Solution for 1/6(2c-1)=1/3c-1/6 equation: 


c in (-oo:+oo)

(1/6)*(2*c-1) = (1/3)*c-(1/6) // - (1/3)*c-(1/6)

(1/6)*(2*c-1)-((1/3)*c)+1/6 = 0

(1/6)*(2*c-1)+(-1/3)*c+1/6 = 0

1/6*(2*c-1)-c/3+1/6 = 0

(1/6*3*6*(2*c-1))/(3*6)+(6*(-c))/(3*6)+(1*3)/(3*6) = 0

1/6*3*6*(2*c-1)+6*(-c)+1*3 = 0

3-3 = 0

0 = 0

0/(3*6) = 0

0/(3*6) = 0 // * 3*6

0 = 0

c belongs to the empty set

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