1/6(2s-1)=1/3s-1/6

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Solution for 1/6(2s-1)=1/3s-1/6 equation: 


s in (-oo:+oo)

(1/6)*(2*s-1) = (1/3)*s-(1/6) // - (1/3)*s-(1/6)

(1/6)*(2*s-1)-((1/3)*s)+1/6 = 0

(1/6)*(2*s-1)+(-1/3)*s+1/6 = 0

1/6*(2*s-1)-s/3+1/6 = 0

(1/6*3*6*(2*s-1))/(3*6)+(6*(-s))/(3*6)+(1*3)/(3*6) = 0

1/6*3*6*(2*s-1)+6*(-s)+1*3 = 0

3-3 = 0

0 = 0

0/(3*6) = 0

0/(3*6) = 0 // * 3*6

0 = 0

s belongs to the empty set

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