1/6(2x+4)=13

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Solution for 1/6(2x+4)=13 equation: 



1/6(2x+4)=13

We move all terms to the left:

1/6(2x+4)-(13)=0



Domain of the equation: 6(2x+4)!=0

x∈R



We multiply all the terms by the denominator


-13*6(2x+4)+1=0

Wy multiply elements

-78x(2+1=0

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