1/6(2x+80)=3x

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Solution for 1/6(2x+80)=3x equation: 


x in (-oo:+oo)

(1/6)*(2*x+80) = 3*x // - 3*x

(1/6)*(2*x+80)-(3*x) = 0

(1/6)*(2*x+80)-3*x = 0

1/6*(2*x+80)-3*x = 0

1/6*(2*x+80)-3*x = 0

40/3-8/3*x = 0

40/3-8/3*x = 0

40/3-8/3*x = 0 // - 40/3

-8/3*x = -40/3 // : -8/3

x = -40/3/(-8/3)

x = 5

x = 5

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