1/6(2x-64)=3x

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Solution for 1/6(2x-64)=3x equation: 



1/6(2x-64)=3x

We move all terms to the left:

1/6(2x-64)-(3x)=0



Domain of the equation: 6(2x-64)!=0

x∈R



We add all the numbers together, and all the variables

-3x+1/6(2x-64)=0

We multiply all the terms by the denominator


-3x*6(2x-64)+1=0

Wy multiply elements

-18x^2(2+1=0

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