1/6(3(x-1)+12)=x

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Solution for 1/6(3(x-1)+12)=x equation: 



1/6(3(x-1)+12)=x

We move all terms to the left:

1/6(3(x-1)+12)-(x)=0



Domain of the equation: 6(3(x-1)+12)!=0

x∈R



We add all the numbers together, and all the variables

-1x+1/6(3(x-1)+12)=0

We multiply all the terms by the denominator


-1x*6(3(x-1)+12)+1=0

Wy multiply elements

-6x^2(3+1=0

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