1/6(3+2x)=1/3x

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Solution for 1/6(3+2x)=1/3x equation: 



1/6(3+2x)=1/3x

We move all terms to the left:

1/6(3+2x)-(1/3x)=0



Domain of the equation: 6(3+2x)!=0

x∈R





Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/6(2x+3)-(+1/3x)=0

We get rid of parentheses

1/6(2x+3)-1/3x=0

We calculate fractions


3x/(36x^2+54x)+(-6x2/(36x^2+54x)=0



We calculate terms in parentheses: +(-6x2/(36x^2+54x), so:

-6x2/(36x^2+54x

We multiply all the terms by the denominator


-6x2

We add all the numbers together, and all the variables

-6x^2

Back to the equation:

+(-6x^2)



We get rid of parentheses

-6x^2+3x/(36x^2+54x)=0

We multiply all the terms by the denominator


-6x^2*(36x^2+54x)+3x=0

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