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1/6(36x-12)=-5x=10
We move all terms to the left:
1/6(36x-12)-(-5x)=0
Domain of the equation: 6(36x-12)!=0We get rid of parentheses
x∈R
1/6(36x-12)+5x=0
We multiply all the terms by the denominator
5x*6(36x-12)+1=0
Wy multiply elements
30x^2(3+1=0
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