1/6(3t-8)=7/6t-(t-8)/12

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Solution for 1/6(3t-8)=7/6t-(t-8)/12 equation: 


t in (-oo:+oo)

(1/6)*(3*t-8) = (7/6)*t-((t-8)/12) // - (7/6)*t-((t-8)/12)

(1/6)*(3*t-8)+(t-8)/12-((7/6)*t) = 0

(1/6)*(3*t-8)+(t-8)/12+(-7/6)*t = 0

1/6*(3*t-8)+(t-8)/12+(-7*t)/6 = 0

(1/6*6*12*(3*t-8))/(6*12)+(6*(t-8))/(6*12)+(-7*12*t)/(6*12) = 0

1/6*6*12*(3*t-8)+6*(t-8)-7*12*t = 0

42*t-84*t-144 = 0

-42*t-144 = 0

(-42*t-144)/(6*12) = 0

(-42*t-144)/(6*12) = 0 // * 6*12

-42*t-144 = 0

-42*t-144 = 0 // + 144

-42*t = 144 // : -42

t = 144/(-42)

t = -24/7

t = -24/7

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