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1/6(3x+3)-3/2(x-5)=1
We move all terms to the left:
1/6(3x+3)-3/2(x-5)-(1)=0
Domain of the equation: 6(3x+3)!=0
x∈R
Domain of the equation: 2(x-5)!=0We calculate fractions
x∈R
(2xx/(6(3x+3)*2(x-5))+(-18x3/(6(3x+3)*2(x-5))-1=0
We can not solve this equation
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