1/6(3x-1)=2/3(x-2)

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Solution for 1/6(3x-1)=2/3(x-2) equation: 



1/6(3x-1)=2/3(x-2)

We move all terms to the left:

1/6(3x-1)-(2/3(x-2))=0



Domain of the equation: 6(3x-1)!=0

x∈R





Domain of the equation: 3(x-2))!=0

x∈R



We calculate fractions


(3xx/(6(3x-1)*3(x-2)))+(-12x3/(6(3x-1)*3(x-2)))=0



We calculate terms in parentheses: +(3xx/(6(3x-1)*3(x-2))), so:

3xx/(6(3x-1)*3(x-2))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-12x3/(6(3x-1)*3(x-2))), so:

-12x3/(6(3x-1)*3(x-2))

We multiply all the terms by the denominator


-12x3

We add all the numbers together, and all the variables

-12x^3

We do not support expression: x^3

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