1/6(42-12x)=3/8(16x+56)

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Solution for 1/6(42-12x)=3/8(16x+56) equation:


1/6(42-12x)=3/8(16x+56)

We simplify the equation to the form, which is simple to understand
1/6(42-12x)=3/8(16x+56)

Simplifying:
+ 0.166666666667*(42-12x)=3/8*(16x+56)

Simplifying:
+ 0.166666666667*(42-12x)=0.375*(16x+56)

Reorder the terms in parentheses
+(+7-2x)=0.375*(16x+56)

Remove unnecessary parentheses
+7-2x=0.375+*(+16x+56+)

Reorder the terms in parentheses
+7-2x=+(+6x+21)

Remove unnecessary parentheses
+7-2x=+6x+21

We move all terms containing x to the left and all other terms to the right.
-2x-6x=+21-7

We simplify left and right side of the equation.
-8x=+14

We divide both sides of the equation by -8 to get x.
x=-1.75

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