1/6(4c+5)=2/3c

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Solution for 1/6(4c+5)=2/3c equation: 



1/6(4c+5)=2/3c

We move all terms to the left:

1/6(4c+5)-(2/3c)=0



Domain of the equation: 6(4c+5)!=0

c∈R





Domain of the equation: 3c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

1/6(4c+5)-(+2/3c)=0

We get rid of parentheses

1/6(4c+5)-2/3c=0

We calculate fractions


3c/(72c^2+90c)+(-12c4/(72c^2+90c)=0



We calculate terms in parentheses: +(-12c4/(72c^2+90c), so:

-12c4/(72c^2+90c

We multiply all the terms by the denominator


-12c4

We add all the numbers together, and all the variables

-12c^4

We do not support ecpression: c^4

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