1/6(4x+24)=6+2/3(x-3)

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Solution for 1/6(4x+24)=6+2/3(x-3) equation: 



1/6(4x+24)=6+2/3(x-3)

We move all terms to the left:

1/6(4x+24)-(6+2/3(x-3))=0



Domain of the equation: 6(4x+24)!=0

x∈R





Domain of the equation: 3(x-3))!=0

x∈R



We calculate fractions


(3xx/(6(4x+24)*3(x-3)))+(-12x4/(6(4x+24)*3(x-3)))=0



We calculate terms in parentheses: +(3xx/(6(4x+24)*3(x-3))), so:

3xx/(6(4x+24)*3(x-3))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-12x4/(6(4x+24)*3(x-3))), so:

-12x4/(6(4x+24)*3(x-3))

We multiply all the terms by the denominator


-12x4

We add all the numbers together, and all the variables

-12x^4

We do not support expression: x^4

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