1/6(4y+5)-2/3(2y+7)=3/2

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Solution for 1/6(4y+5)-2/3(2y+7)=3/2 equation: 



1/6(4y+5)-2/3(2y+7)=3/2

We move all terms to the left:

1/6(4y+5)-2/3(2y+7)-(3/2)=0



Domain of the equation: 6(4y+5)!=0

y∈R





Domain of the equation: 3(2y+7)!=0

y∈R



We add all the numbers together, and all the variables

1/6(4y+5)-2/3(2y+7)-(+3/2)=0

We get rid of parentheses

1/6(4y+5)-2/3(2y+7)-3/2=0

We calculate fractions


(6y2/(6(4y+5)*3(2y+7)*2)+(-24y4/(6(4y+5)*3(2y+7)*2)+(-54y^24/(6(4y+5)*3(2y+7)*2)=0



We calculate terms in parentheses: +(6y2/(6(4y+5)*3(2y+7)*2)+(-24y4/(6(4y+5)*3(2y+7)*2)+(-54y^24/(6(4y+5)*3(2y+7)*2), so:

6y2/(6(4y+5)*3(2y+7)*2)+(-24y4/(6(4y+5)*3(2y+7)*2)+(-54y^24/(6(4y+5)*3(2y+7)*2

We do not support eypression: y^24

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