1/6(5s+3)=1/2(s+1)

Solution for 1/6(5s+3)=1/2(s+1) equation:

1/6(5s+3)=1/2(s+1)

We move all terms to the left:

1/6(5s+3)-(1/2(s+1))=0


Domain of the equation: 6(5s+3)!=0

s∈R



Domain of the equation: 2(s+1))!=0

s∈R


We calculate fractions


(2ss/(6(5s+3)*2(s+1)))+(-6s5/(6(5s+3)*2(s+1)))=0


We calculate terms in parentheses: +(2ss/(6(5s+3)*2(s+1))), so:

2ss/(6(5s+3)*2(s+1))

We multiply all the terms by the denominator


2ss

Back to the equation:

+(2ss)



We calculate terms in parentheses: +(-6s5/(6(5s+3)*2(s+1))), so:

-6s5/(6(5s+3)*2(s+1))

We multiply all the terms by the denominator


-6s5

We add all the numbers together, and all the variables

-6s^5

We do not support espression: s^5