1/6(5x+2)=7

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Solution for 1/6(5x+2)=7 equation: 



1/6(5x+2)=7

We move all terms to the left:

1/6(5x+2)-(7)=0



Domain of the equation: 6(5x+2)!=0

x∈R



We multiply all the terms by the denominator


-7*6(5x+2)+1=0

Wy multiply elements

-42x(5+1=0

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