1/6(5x+3)=1/2(x+11)

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Solution for 1/6(5x+3)=1/2(x+11) equation: 



1/6(5x+3)=1/2(x+11)

We move all terms to the left:

1/6(5x+3)-(1/2(x+11))=0



Domain of the equation: 6(5x+3)!=0

x∈R





Domain of the equation: 2(x+11))!=0

x∈R



We calculate fractions


(2xx/(6(5x+3)*2(x+11)))+(-6x5/(6(5x+3)*2(x+11)))=0



We calculate terms in parentheses: +(2xx/(6(5x+3)*2(x+11))), so:

2xx/(6(5x+3)*2(x+11))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)





We calculate terms in parentheses: +(-6x5/(6(5x+3)*2(x+11))), so:

-6x5/(6(5x+3)*2(x+11))

We multiply all the terms by the denominator


-6x5

We add all the numbers together, and all the variables

-6x^5

We do not support expression: x^5

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