1/6(a-4)=1/3(3a+4)

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Solution for 1/6(a-4)=1/3(3a+4) equation: 



1/6(a-4)=1/3(3a+4)

We move all terms to the left:

1/6(a-4)-(1/3(3a+4))=0



Domain of the equation: 6(a-4)!=0

a∈R





Domain of the equation: 3(3a+4))!=0

a∈R



We calculate fractions


(3a3/(6(a-4)*3(3a+4)))+(-6aa/(6(a-4)*3(3a+4)))=0



We calculate terms in parentheses: +(3a3/(6(a-4)*3(3a+4))), so:

3a3/(6(a-4)*3(3a+4))

We multiply all the terms by the denominator


3a3

We add all the numbers together, and all the variables

3a^3

We do not support eapression: a^3

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