1/6(b+6)=1/4b+

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Solution for 1/6(b+6)=1/4b+ equation: 



1/6(b+6)=1/4b+

We move all terms to the left:

1/6(b+6)-(1/4b+)=0



Domain of the equation: 6(b+6)!=0

b∈R





Domain of the equation: 4b+)!=0

b∈R



We add all the numbers together, and all the variables

1/6(b+6)-(+1/4b)=0

We get rid of parentheses

1/6(b+6)-1/4b=0

We calculate fractions


4b/(24b^2+144b)+(-6bb/(24b^2+144b)=0



We calculate terms in parentheses: +(-6bb/(24b^2+144b), so:

-6bb/(24b^2+144b

We multiply all the terms by the denominator


-6bb

Back to the equation:

+(-6bb)



We get rid of parentheses

4b/(24b^2+144b)-6bb=0

We multiply all the terms by the denominator


4b-6bb*(24b^2+144b)=0

We multiply parentheses

-144b^3-864b^2+4b=0

We do not support ebpression: b^3

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