1/6(k2-18)=22-3

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Solution for 1/6(k2-18)=22-3 equation: 



1/6(k2-18)=22-3

We move all terms to the left:

1/6(k2-18)-(22-3)=0



Domain of the equation: 6(k2-18)!=0

k∈R



We add all the numbers together, and all the variables

1/6(+k^2-18)-19=0

We multiply all the terms by the denominator


-19*6(+k^2-18)+1=0

Wy multiply elements

-114k(++1=0

We use the square of the difference formula

-114k(+1=0

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