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1/6(x+2)-1/9(2x-3)=1/12(1-3x)
We move all terms to the left:
1/6(x+2)-1/9(2x-3)-(1/12(1-3x))=0
Domain of the equation: 6(x+2)!=0
x∈R
Domain of the equation: 9(2x-3)!=0
x∈R
Domain of the equation: 12(1-3x))!=0We add all the numbers together, and all the variables
x∈R
1/6(x+2)-1/9(2x-3)-(1/12(-3x+1))=0
We calculate fractions
(-72x^2x/(6(x+2)*9(2x-3)*12(-3x+1)))+(-54x^2x/(6(x+2)*9(2x-3)*12(-3x+1)))+(108x^22/(6(x+2)*9(2x-3)*12(-3x+1)))=0
We calculate terms in parentheses: +(-72x^2x/(6(x+2)*9(2x-3)*12(-3x+1))), so:
-72x^2x/(6(x+2)*9(2x-3)*12(-3x+1))
We multiply all the terms by the denominator
-72x^2x
Back to the equation:
+(-72x^2x)
We calculate terms in parentheses: +(-54x^2x/(6(x+2)*9(2x-3)*12(-3x+1))), so:
-54x^2x/(6(x+2)*9(2x-3)*12(-3x+1))
We multiply all the terms by the denominator
-54x^2x
Back to the equation:
+(-54x^2x)
We calculate terms in parentheses: +(108x^22/(6(x+2)*9(2x-3)*12(-3x+1))), so:
108x^22/(6(x+2)*9(2x-3)*12(-3x+1))
We do not support expression: x^22
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