1/6(x+2)=2x-5(4-x)-7

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Solution for 1/6(x+2)=2x-5(4-x)-7 equation: 


x in (-oo:+oo)

(1/6)*(x+2) = 2*x-(5*(4-x))-7 // - 2*x-(5*(4-x))-7

(1/6)*(x+2)+5*(4-x)-(2*x)+7 = 0

(1/6)*(x+2)+5*(4-x)-2*x+7 = 0

1/6*(x+2)+5*(4-x)-2*x+7 = 0

1/6*(x+2)+5*(4-x)-2*x+7 = 0

7-29/6*x-2*x+61/3 = 0

7-41/6*x+61/3 = 0

82/3-41/6*x = 0

82/3-41/6*x = 0

82/3-41/6*x = 0 // - 82/3

-41/6*x = -82/3 // : -41/6

x = -82/3/(-41/6)

x = 4

x = 4

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