1/6(x+3)=1/5(x-4)=1

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Solution for 1/6(x+3)=1/5(x-4)=1 equation: 



1/6(x+3)=1/5(x-4)=1

We move all terms to the left:

1/6(x+3)-(1/5(x-4))=0



Domain of the equation: 6(x+3)!=0

x∈R





Domain of the equation: 5(x-4))!=0

x∈R



We calculate fractions


(5xx/(6(x+3)*5(x-4)))+(-6xx/(6(x+3)*5(x-4)))=0



We calculate terms in parentheses: +(5xx/(6(x+3)*5(x-4))), so:

5xx/(6(x+3)*5(x-4))

We multiply all the terms by the denominator


5xx

Back to the equation:

+(5xx)





We calculate terms in parentheses: +(-6xx/(6(x+3)*5(x-4))), so:

-6xx/(6(x+3)*5(x-4))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

5xx-6xx=0

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