1/6(x+4)=1/3(2x+4)

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Solution for 1/6(x+4)=1/3(2x+4) equation: 



1/6(x+4)=1/3(2x+4)

We move all terms to the left:

1/6(x+4)-(1/3(2x+4))=0



Domain of the equation: 6(x+4)!=0

x∈R





Domain of the equation: 3(2x+4))!=0

x∈R



We calculate fractions


(3x2/(6(x+4)*3(2x+4)))+(-6xx/(6(x+4)*3(2x+4)))=0



We calculate terms in parentheses: +(3x2/(6(x+4)*3(2x+4))), so:

3x2/(6(x+4)*3(2x+4))

We multiply all the terms by the denominator


3x2

We add all the numbers together, and all the variables

3x^2

Back to the equation:

+(3x^2)





We calculate terms in parentheses: +(-6xx/(6(x+4)*3(2x+4))), so:

-6xx/(6(x+4)*3(2x+4))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

3x^2-6xx=0

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