1/6(x-1)=1/3(3x+2)

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Solution for 1/6(x-1)=1/3(3x+2) equation: 



1/6(x-1)=1/3(3x+2)

We move all terms to the left:

1/6(x-1)-(1/3(3x+2))=0



Domain of the equation: 6(x-1)!=0

x∈R





Domain of the equation: 3(3x+2))!=0

x∈R



We calculate fractions


(3x3/(6(x-1)*3(3x+2)))+(-6xx/(6(x-1)*3(3x+2)))=0



We calculate terms in parentheses: +(3x3/(6(x-1)*3(3x+2))), so:

3x3/(6(x-1)*3(3x+2))

We multiply all the terms by the denominator


3x3

We add all the numbers together, and all the variables

3x^3

We do not support expression: x^3

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