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1/6(x-18)+1/2(x+2)=x+4
We move all terms to the left:
1/6(x-18)+1/2(x+2)-(x+4)=0
Domain of the equation: 6(x-18)!=0
x∈R
Domain of the equation: 2(x+2)!=0We get rid of parentheses
x∈R
1/6(x-18)+1/2(x+2)-x-4=0
We calculate fractions
-x+(2xx/(6(x-18)*2(x+2))+(6xx/(6(x-18)*2(x+2))-4=0
We can not solve this equation
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