1/6(x-18)+1/2(x+2)=x+4

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Solution for 1/6(x-18)+1/2(x+2)=x+4 equation: 



1/6(x-18)+1/2(x+2)=x+4

We move all terms to the left:

1/6(x-18)+1/2(x+2)-(x+4)=0



Domain of the equation: 6(x-18)!=0

x∈R





Domain of the equation: 2(x+2)!=0

x∈R



We get rid of parentheses

1/6(x-18)+1/2(x+2)-x-4=0

We calculate fractions


-x+(2xx/(6(x-18)*2(x+2))+(6xx/(6(x-18)*2(x+2))-4=0

We can not solve this equation

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