1/6(x-2)=1/8(x+2)

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Solution for 1/6(x-2)=1/8(x+2) equation:



1/6(x-2)=1/8(x+2)
We move all terms to the left:
1/6(x-2)-(1/8(x+2))=0
Domain of the equation: 6(x-2)!=0
x∈R
Domain of the equation: 8(x+2))!=0
x∈R
We calculate fractions
(8xx/(6(x-2)*8(x+2)))+(-6xx/(6(x-2)*8(x+2)))=0
We calculate terms in parentheses: +(8xx/(6(x-2)*8(x+2))), so:
8xx/(6(x-2)*8(x+2))
We multiply all the terms by the denominator
8xx
Back to the equation:
+(8xx)
We calculate terms in parentheses: +(-6xx/(6(x-2)*8(x+2))), so:
-6xx/(6(x-2)*8(x+2))
We multiply all the terms by the denominator
-6xx
Back to the equation:
+(-6xx)
We get rid of parentheses
8xx-6xx=0

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