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1/6(x-36)=5+2x
We move all terms to the left:
1/6(x-36)-(5+2x)=0
Domain of the equation: 6(x-36)!=0We add all the numbers together, and all the variables
x∈R
1/6(x-36)-(2x+5)=0
We get rid of parentheses
1/6(x-36)-2x-5=0
We multiply all the terms by the denominator
-2x*6(x-36)-5*6(x-36)+1=0
Wy multiply elements
-12x^2(x-30x(x+1=0
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