1/6(x-4)=3+2x

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Solution for 1/6(x-4)=3+2x equation: 



1/6(x-4)=3+2x

We move all terms to the left:

1/6(x-4)-(3+2x)=0



Domain of the equation: 6(x-4)!=0

x∈R



We add all the numbers together, and all the variables

1/6(x-4)-(2x+3)=0

We get rid of parentheses

1/6(x-4)-2x-3=0

We multiply all the terms by the denominator


-2x*6(x-4)-3*6(x-4)+1=0

Wy multiply elements

-12x^2(x-18x(x+1=0

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