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1/6(x-5)=1/2(x-6)
We move all terms to the left:
1/6(x-5)-(1/2(x-6))=0
Domain of the equation: 6(x-5)!=0
x∈R
Domain of the equation: 2(x-6))!=0We calculate fractions
x∈R
(2xx/(6(x-5)*2(x-6)))+(-6xx/(6(x-5)*2(x-6)))=0
We calculate terms in parentheses: +(2xx/(6(x-5)*2(x-6))), so:
2xx/(6(x-5)*2(x-6))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-6xx/(6(x-5)*2(x-6))), so:We get rid of parentheses
-6xx/(6(x-5)*2(x-6))
We multiply all the terms by the denominator
-6xx
Back to the equation:
+(-6xx)
2xx-6xx=0
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