1/6(y+42)-15=3

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Solution for 1/6(y+42)-15=3 equation: 



1/6(y+42)-15=3

We move all terms to the left:

1/6(y+42)-15-(3)=0



Domain of the equation: 6(y+42)!=0

y∈R



We add all the numbers together, and all the variables

1/6(y+42)-18=0

We multiply all the terms by the denominator


-18*6(y+42)+1=0

Wy multiply elements

-108y(y+1=0

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