1/6*x+2/3*x=5

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Solution for 1/6*x+2/3*x=5 equation:



1/6*x+2/3*x=5
We move all terms to the left:
1/6*x+2/3*x-(5)=0
Domain of the equation: 6*x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3*x!=0
x!=0/1
x!=0
x∈R
We calculate fractions
3x^2/54x^2+12x^2/54x^2-5=0
We multiply all the terms by the denominator
3x^2+12x^2-5*54x^2=0
We add all the numbers together, and all the variables
15x^2-5*54x^2=0
Wy multiply elements
15x^2-270x^2=0
We add all the numbers together, and all the variables
-255x^2=0
a = -255; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-255)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-510}=0$

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