1/6*x+2/3*x=5

Solution for 1/6*x+2/3*x=5 equation:

1/6*x+2/3*x=5

We move all terms to the left:

1/6*x+2/3*x-(5)=0


Domain of the equation: 6*x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3*x!=0

x!=0/1

x!=0

x∈R


We calculate fractions


3x^2/54x^2+12x^2/54x^2-5=0

We multiply all the terms by the denominator


3x^2+12x^2-5*54x^2=0

We add all the numbers together, and all the variables

15x^2-5*54x^2=0

Wy multiply elements

15x^2-270x^2=0

We add all the numbers together, and all the variables

-255x^2=0

a = -255; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-255)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-510}=0$