1/6+1/3(x-3)=1/2(x+9)

Solution for 1/6+1/3(x-3)=1/2(x+9) equation:

1/6+1/3(x-3)=1/2(x+9)

We move all terms to the left:

1/6+1/3(x-3)-(1/2(x+9))=0


Domain of the equation: 3(x-3)!=0

x∈R



Domain of the equation: 2(x+9))!=0

x∈R


We calculate fractions


(12xx/(3(x-3)*2(x+9))*6)+(-(1*3(x-3)*6)/(3(x-3)*2(x+9))*6)+(6x^2x/(3(x-3)*2(x+9))*6)=0


We calculate terms in parentheses: +(12xx/(3(x-3)*2(x+9))*6), so:

12xx/(3(x-3)*2(x+9))*6

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)



We calculate terms in parentheses: +(-(1*3(x-3)*6)/(3(x-3)*2(x+9))*6), so:

-(1*3(x-3)*6)/(3(x-3)*2(x+9))*6

We multiply all the terms by the denominator


-(1*3(x-3)*6)


We calculate terms in parentheses: -(1*3(x-3)*6), so:

1*3(x-3)*6

Wy multiply elements

18x(x

Back to the equation:

-(18x(x)


Back to the equation:

+(-(18xx)



We calculate terms in parentheses: +(6x^2x/(3(x-3)*2(x+9))*6), so:

6x^2x/(3(x-3)*2(x+9))*6

We multiply all the terms by the denominator


6x^2x

Back to the equation:

+(6x^2x)


determiningTheFunctionDomain
(-18xx+6x^2x+12xx=0