1/6+d+2/3=1/4(d-2)

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Solution for 1/6+d+2/3=1/4(d-2) equation: 



1/6+d+2/3=1/4(d-2)

We move all terms to the left:

1/6+d+2/3-(1/4(d-2))=0



Domain of the equation: 4(d-2))!=0

d∈R



We calculate fractions


d+()/(4(d-2))*6*3)+(12dd/(4(d-2))*6*3)+(48dd/(4(d-2))*6*3)=0



We calculate terms in parentheses: +()/(4(d-2))*6*3)+(12dd/(4(d-2))*6*3)+(48dd/(4(d-2))*6*3), so:

)/(4(d-2))*6*3)+(12dd/(4(d-2))*6*3)+(48dd/(4(d-2))*6*3

We can not solve this equation

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