1/60x+2=1/40x

Solution for 1/60x+2=1/40x equation:

1/60x+2=1/40x

We move all terms to the left:

1/60x+2-(1/40x)=0


Domain of the equation: 60x!=0

x!=0/60

x!=0

x∈R



Domain of the equation: 40x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/60x-(+1/40x)+2=0

We get rid of parentheses

1/60x-1/40x+2=0

We calculate fractions


40x/2400x^2+(-60x)/2400x^2+2=0

We multiply all the terms by the denominator


40x+(-60x)+2*2400x^2=0

Wy multiply elements

4800x^2+40x+(-60x)=0

We get rid of parentheses

4800x^2+40x-60x=0

We add all the numbers together, and all the variables

4800x^2-20x=0

a = 4800; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·4800·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*4800}=\frac{0}{9600}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*4800}=\frac{40}{9600}
=1/240
$