If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5;7;2;1;2;0
x^2*(((4*x-1)*(x+1)*(2*x+1))/4)-1
12.277 = 1/h
x^2*(((4*x-1)*(x+1)*(2*x+1))/4)-1
-40 = y/7
| -(x+3)=3x+1 | | 7(4x+13)= | | 12.277=1/h | | 4x^2+78+360=0 | | -9x+7=25+(5-x) | | -40=y/7 | | 3x+30=2x+102 | | -1.59+X=3.96 | | v-2.3=4.87 | | 5(3x+5)=15x-1 | | -x+10=8 | | x+3=5(2x+3) | | 3m-7n=1 | | 28+23a=35-16a | | 1.5x+30+2x=180 | | 196=-10n-6 | | 7=6/2x | | 294=238-w | | r-2/r-3=3/9 | | 4b+10=6b+2 | | -148=8x-4 | | 6x+8=4x+54 | | 6x+19=97 | | 5(w+1)=9w+13 | | 6x-4y=-7 | | 28+23a=35+16a | | 3(x-6)+2x=22 | | 208=140-u | | X-4=-2x+14 | | 9y+9=8y-3 | | -20x=-180 | | 3x^3-9x^2+1=0 |